8x^2-4=14x

Solution for 8x^2-4=14x equation:

8x^2-4=14x

We move all terms to the left:

8x^2-4-(14x)=0

a = 8; b = -14; c = -4;
Δ = b2-4ac
Δ = -142-4·8·(-4)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-18}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+18}{2*8}=\frac{32}{16}
=2
$